Mathématiques

Question

Svp aidez moi.
factoriser: 4 (x+1)^2-(x-2)(2x+2)
(2x-7)(3x+6)-2 (2x+4)(2x-8)
9x^2+6x+1-(5x+7)(6x+2)

2 Réponse

  • bonjour,

    : 4 (x+1)^2-(x-2)(2x+2)
    4(x+1)²-2(x-2)(x+1) =
    (x+1)[4(x+1)-2(x-2)] =
    (x+1)(4x+4-2x+4) =
    (x+1)(2x+8)=
    2(x+1)(x+4)

    (2x-7)(3x+6)-2 (2x+4)(2x-8) sur de l'énoncé ?

    9x^2+6x+1-(5x+7)(6x+2)
    (3x+1)²-2(5x+7)(3x+1) =
    (3x+1)(3x+1-10x-14) =
    (3x+1)(-7x-13)

  • bonjour

    4 (x+1)^2-(x-2)(2x+2)
    4(x+1)² -2(x-2)(x+1)
    (x+1)(4x+4-2x-4)
    (x+1)(2x)
    2x(x+1)


    (2x-7)(3x+6)-2 (2x+4)(2x-8)
    3(2x-7)(x+2) -4(x+2)(2x-8)
    (x+2)(6x-21-8x+36)
    (x+2)(-2x+15)

     9x^2+6x+1-(5x+7)(6x+2)
    (3x+1)² -2(5x+7)(3x+1)
    (3x+1)(3x+1-10x-14)
    (3x+1)(-7x-13)

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