Mathématiques

Question

aidez moi merci

factoriser:
E = (4x - 6)² - (2x - 4)²
F = (6x + 8)² - (3x - 4)²
G = (4x + 5)² - 81
H = 64 - (4x - 2)²


developper:
I = (7x + 4) (7x -4)
J= (8 - 2x) (8 + 2x)
K = (1 + 10x) ( 1 - 10x)
L = (8x + 2) (8x - 2)

2 Réponse

  • bonjour

    E = ( 4 x - 6 + 2 x - 4) ( 4 x - 6 - 2 x + 4)
    E = ( 6 x - 10) ( 2 x - 2)

    F = ( 6 x + 8 + 3 x - 4) ( 6 x + 8 - 3 x + 4)
    F = ( 9 x + 4) ( 3 x + 12)
     tu fais seule G et H, ce  sont aussi des différences de carrés : 81 = 9² et 64 = 8²

    I = 49 x² - 16

    c'est pareil mais l'exercice inverse, ce sont des carrés donc a² - b²


  • Bonjour

    E =  (4x - 6)² - (2x - 4)²
    E = (4x - 6 + 2x - 4) ( 4x - 6 - 2x + 4)
    E = (4x + 2x - 6 - 4) (4x - 2x - 6 + 4)
    E = (6x - 10) ( 2x - 2)

    F = (6x + 8)² - (3x - 4)²
    F = (6x + 8 + 3x - 4) ( 6x + 8 - 3x + 4)
    F = (6x + 3x + 8 - 4) (6x - 3x + 8 + 4)
    F = (9x + 4) (3x + 12)

    G = (4x + 5)² - 81
    G = (4x + 5) - 9²
    G = (4x + 5 - 9) (4x + 5 + 9)
    G = (4x - 4) (4x + 14)

    H = 64 - (4x - 2)²
    H = 8² - (4x - 2)²
    H = (8 - 4x - 2) (8 + 4x - 2)
    H = (10 - 4x) (6 + 4x)

    I = (7x + 4) (7x -4)
    I = 49x² - 28x - 28x - 16
    I = 49x² - 16

    J= (8 - 2x) (8 + 2x)
    J = 64 + 16x - 16x - 4x²
    J = - 4x² + 64

    K = (1 + 10x) ( 1 - 10x)
    K = 1 - 10x + 10x - 100x²
    K = - 100x² + 1

    L = (8x + 2) (8x - 2)
    L = 64x² - 16x + 16x - 4
    L = 64x² - 4

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