Mathématiques

Question

résoudre l'inequation 100x+(140x)>(140-x)(100-x)

1 Réponse

  • Bonjour

    Résoudre l'inéquation :

    100x+(140x)>(140-x)(100-x)

    100x + 140x > 14000 - 140x - 100x + x^2

    x^2 - 240x - 240x + 14000 < 0

    x^2 - 480x + 14000 < 0

    [tex]\Delta = (-480)^{2} - 4 \times 1 \times 14000 = 230400 - 56000 = 174400[/tex]

    [tex]\sqrt\Delta \approx 417,6[/tex]

    X1 = (480 - 417,6)/2 = 62,4/2 = 31,2

    X2 = (480 + 417,6)/2 = 448,8

    (X - 31,2)(x - 448,8) < 0

    X..............|-inf..........(31,2)............(448,8).....+inf

    x-31,2......|.........(-).......o........(+).................(+)......

    x-448,8..|.........(-)...................(-).........o......(+).......

    Ineq.......|..........(+)........||.........(-).........||.......(+).......


    x € ]31,2 ; 448,8 [

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