résoudre l'inequation 100x+(140x)>(140-x)(100-x)
Mathématiques
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Question
résoudre l'inequation 100x+(140x)>(140-x)(100-x)
1 Réponse
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1. Réponse loulakar
Bonjour
Résoudre l'inéquation :
100x+(140x)>(140-x)(100-x)
100x + 140x > 14000 - 140x - 100x + x^2
x^2 - 240x - 240x + 14000 < 0
x^2 - 480x + 14000 < 0
[tex]\Delta = (-480)^{2} - 4 \times 1 \times 14000 = 230400 - 56000 = 174400[/tex]
[tex]\sqrt\Delta \approx 417,6[/tex]
X1 = (480 - 417,6)/2 = 62,4/2 = 31,2
X2 = (480 + 417,6)/2 = 448,8
(X - 31,2)(x - 448,8) < 0
X..............|-inf..........(31,2)............(448,8).....+inf
x-31,2......|.........(-).......o........(+).................(+)......
x-448,8..|.........(-)...................(-).........o......(+).......
Ineq.......|..........(+)........||.........(-).........||.......(+).......
x € ]31,2 ; 448,8 [